Yea...this is Dustin. The past 2 weeks, we learned a lot of nonsense about limits. So, i'll explain how limits work and stuff.
Ex. Lim x+2
x->2
For this simple problem, you would just plug in 2 for all appearances of "x".
You would then receive the simple problem 2+2, which is like 4 or something.
Limits also can be more complicating than just plugging in numbas. You might have to factor like this one here:
Ex. Lim (x^2+x-2)/(x+2)
x->-2
For this problem if you were to simply plug in the -2 you would then have to divide by zero, which is kinda tough to do. So instead, we will factor the top and get:
((x+2)(x-1))/(x+2)
Which simplifies to:
(x-1)
Then we plug in the -2 and get:
-2-1
Which is (-3).
Yea, so that's basically limits. You just plug in to the equation. If you get a whole number, then that's your answer, but if you get something divided by zero, you have to either factor, squeeze, create a chart, or some other over complicated method.
And um, something I don't understand is how to find the difference of 2 cubes, so if someone is rather smart could you, um, maybe help me or something like that. I guess that's it, and I hope that's enough words.
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